A clock regulated by a second's pendulum keeps correct time. During summer the length of the pendulum increases to 1.02 m. How much will the clock gain or lose in one day?
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Answered by
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1 answer · Physics
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Pendulum period in seconds
T ≈ 2π√(L/g)
or, rearranging:
g ≈ 4π²L/T²
L ≈ T²g/4π²
L is length of pendulum in meters
g is gravitational acceleration = 9.8 m/s²
The pendulum length is not mentioned, so I assume you have to calculate it from the above.
period is 1 second.
L ≈ (1)²g/4π² = 0.248 m. That size expanding to 1.1 meters doesn't make sense.
I think you left part of the problem out, or copied it incorrectly.
hope it helps
pls mark as brainliest
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Best Answer
Pendulum period in seconds
T ≈ 2π√(L/g)
or, rearranging:
g ≈ 4π²L/T²
L ≈ T²g/4π²
L is length of pendulum in meters
g is gravitational acceleration = 9.8 m/s²
The pendulum length is not mentioned, so I assume you have to calculate it from the above.
period is 1 second.
L ≈ (1)²g/4π² = 0.248 m. That size expanding to 1.1 meters doesn't make sense.
I think you left part of the problem out, or copied it incorrectly.
hope it helps
pls mark as brainliest
✨☺❤❤☺✨
Answered by
0
Answer:
1 answer · Physics
Best Answer
Pendulum period in seconds
T ≈ 2π√(L/g)
or, rearranging:
g ≈ 4π²L/T²
L ≈ T²g/4π²
L is length of pendulum in meters
g is gravitational acceleration = 9.8 m/s²
The pendulum length is not mentioned, so I assume you have to calculate it from the above.
period is 1 second.
L ≈ (1)²g/4π² = 0.248 m. That size expanding to 1.1 meters doesn't make sense.
I think you left part of the problem out, or copied it incorrectly.
hope it helps
pls mark as brainliest
✨☺❤❤☺✨
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