Question

A clock regulated by a second's pendulum keeps correct time. During summer the length of the pendulum increases to 1.02 m. How much will the clock gain or lose in one day?

Answer 1

1 answer · Physics 

 Best Answer

Pendulum period in seconds 
T ≈ 2π√(L/g) 
or, rearranging: 
g ≈ 4π²L/T² 
L ≈ T²g/4π² 
L is length of pendulum in meters 
g is gravitational acceleration = 9.8 m/s² 

The pendulum length is not mentioned, so I assume you have to calculate it from the above. 

period is 1 second. 
L ≈ (1)²g/4π² = 0.248 m. That size expanding to 1.1 meters doesn't make sense. 

I think you left part of the problem out, or copied it incorrectly. 


hope it helps
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Answer 2

Answer:

1 answer · Physics 

 Best Answer

Pendulum period in seconds 

T ≈ 2π√(L/g) 

or, rearranging: 

g ≈ 4π²L/T² 

L ≈ T²g/4π² 

L is length of pendulum in meters 

g is gravitational acceleration = 9.8 m/s² 

The pendulum length is not mentioned, so I assume you have to calculate it from the above. 

period is 1 second. 

L ≈ (1)²g/4π² = 0.248 m. That size expanding to 1.1 meters doesn't make sense. 

I think you left part of the problem out, or copied it incorrectly. 

hope it helps

pls mark as brainliest

✨☺❤❤☺✨