Question

a clock with a brass pendulum heats correct time at 20°c but looses 8.212 sec/day when the temp raises to 30°c calculate the coefficient of linear expansion of brass
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Answer 1

Answer:

Explanation:

Loss of time in a day = 1/2 x α x (t2-t1) x 86400

So, 8.212 = 1/2 x α x 10 x 86400

= 19 x 10-6  per ºC.