Question

A closed box 12 cm ,10cm,8cm is painted from outside. The area to be painted is

Answer 1

The area to be painted is 592 cm²

Step-by-step explanation:

GIVEN

Length = 12 cm

Breadth = 10 cm

Height = 8 cm

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TO FIND

The area to be painted

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FORMULAS

Total Surface Area Of Cuboid = 2 × [ ( Length × Breadth ) + ( Breadth × Height ) + ( Height × Length ) ]

Perimeter Of Cuboid = 4 × ( Length + Breadth + Height )

Volume Of Cuboid = Length × Breadth × Height

Diagonal Of Cuboid = √ ( Length² + Breadth² + Height² )

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We know that,

Total Surface Area Of Cuboid = 2 × [ ( Length × Breadth ) + ( Breadth × Height ) + ( Height × Length ) ]

Total Surface Area Of Cuboid = 2 × [ ( 12 × 10 ) + ( 10 × 8 ) + ( 8 × 12 ) ]

Total Surface Area Of Cuboid = 2 × [ 120 + 80 + 96 ]

Total Surface Area Of Cuboid = 2 × 296

Total Surface Area Of Cuboid = 592

Total Surface Area Of Cuboid = 592 cm²

The area to be painted is 592 cm²

Answer 2

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b = breadth

l = length

h = height

→ 2× [(l×b) + (b×h) + (h×l)

→ 2× [(12×10) + (10×8) + (8×12)

→ 2× [120 + 80 + 96]

→ 2× 296

→ 592 Ans.