A closed box is made of wood which is 1.8cm thick. Its external dimensions are 84cm*64cm*50cm. Find
(1) the capacity of the box.
(2) the volume of the wood used in making the box.
(3) the weight of the empty box if 1cm cube of wood weighs 6.8gm
Answers
capacity of the box =225325.824 cm³
The volume of the wood used in making the box. =43474.176 cm³
the weight of the empty box = 295624.39 gm
Step-by-step explanation:
external length = 84 cm
external breadth = 64 cm
external height = 50 cm
thickness = 1.8 cm
internal length = 84- 2(1.8) = 84- 3.6 = 80.4 cm
internal breadth =64- 2(1.8) = 64-3.6 = 60.4
internal height= 50- 2(1.8) = 50 - 3.6 = 46.4 cm
capacity of the box = length ×breadth× height
= 80.4 × 60.4 ×46.4
= 225325.824 cm³
The volume of the wood used in making the box. = external volume - internal volume
= (84×64×50) - 225325.824
= 268800 - 225325.824
= 43474.176 cm³
if 1cm cube of wood weighs= 6.8 gm
then
43474.176 cm³of wood weighs = 43474.176 cm³× 6.8 = 295624.39 gm
hence ,
capacity of the box =225325.824 cm³
The volume of the wood used in making the box. =43474.176 cm³
the weight of the empty box = 295624.39 gm
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Answer:
1) the capacity of the box =225325.824 cm*.
2)the volume of the wood used in the making the box=4347.176 cm*
3)the weight of the empty box if 1cm cube of wood weighs is 6.8gm.=295.624gm.
Step-by-step explanation:
The external dimensions are Length=84cm* Breadth=64cm*Height= 50cm*.
Breadth=64 - 2 X 1.8.
=64-3.6 = 60.4cm
Height= 50-2X1.8.
=50-3.6=46.4cm