Math, asked by 4464, 1 year ago

a closed box is varnished on the outside at the rate of 5p per cm2 what is the total cost of varnished a box of length 50cm breadth 40 cm and height 30 cm

Answers

Answered by shrutirai2908
99
surface area of the box= 2×(50×40+50×30+40×30)
=9400
and area of vanishing outside so area =4700
cost =5p/cm^2
so cost=4700×5
cost=23500p or rs235
Answered by payalchatterje
3

Answer:

The total cost of varnished the box is 470 rupees.

Step-by-step explanation:

Given,a box of length 50cm breadth 40 cm and height 30 cm.

So, length = 50 cm and breadth = 40 cm and height = 30 cm.

We know surface area (SA)=2lb+2lh+2hb.

Where l is length,b is breadth,h is height

Here,

l = 50 \: cm \\ b = 40 \: cm \\ h = 30 \: cm

So, surface area of the box

 = 2(50×40 + 40×30 + 50×30) \\  = 2 \times 4700 \\  = 9400 \:  {cm}^{2}

It is also given that the closed box is varnished on the outside at the rate of 5p per cm².

So, cost of varnishing of 1 cm² is 5 p

By Unitary method,cost of varnishing of 5300 cm² is (9400×5) p = 47000 p

We know 100 p = 1 rupee

So ,47000 p = 470 rupees.

Therefore, required total cost is 470 rupees.

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