Question

A closed box of dimensions 40 cm x 20 cm x 5 cm is made from a sheet of metal. How much sheet of metal is required?
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Answer 1

Answer:

lenth l = 40cm

breathe b = 20cm

height h = 5cm respectively

sheets required = surface area of box(cuboid)

so,

surface area of box = 2×(l×b+l×h+b×h)

= 2(40×20+40×5+20×5)

= 2×(800+200+100)

= 2×1100

= 2200cm² answer

so 2200cm² sheets of metal is required

Answer 2

Given:-

• The dimensions of the closed (cuboid) box are 40cm,20cm and 5cm.

To Find:-

• How much sheet of metal is required?

Concept:-

• Let's go through the concept first. Concept used here is Total Surface Area(TSA) of a Cuboid.Substitute the values in the equation and let's find it out.

Formulae Applied:-

• Total Surface Area (TSA) of a Cuboid = 2(lb + bh + hl)

Solution:-

Length = 40cm

Breadth = 20cm

Height = 5cm

According to the question we have!

Total Surface Area (TSA) of a Cuboid = 2(lb + bh + hl)

⟹ 2(lb + bh + hl)

⟹ 2[(40 × 20) + (20 × 5) + (5 × 40)]

⟹ 2(800 + 100 + 200)

⟹ 2(1100)

⟹ 2 × 1100

⟹ 2200

⟹2200cm^2

Hence,

The sheet of metal required is 2200cm^2.

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