A closed container contains equal no. Of moles of 2 gases Xand Y at a total pressure 710 mm of hg if gas X will remove from the mixture, the pressure will
(a) double
(b) half
(c) remains same
(d) become one - fourth
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3
Answer:
Here in the closed container, the equal number of moles of two gases are taken.
Thus, when gas X is removed, the number of moles of the gases in the container becomes half.
According to an Ideal gas equation,
PV=nRT.
∴P∝n
Thus, if all the other conditions are kept constant, the pressure is directly proportional to the number of moles.
Thus, if the number of moles of the gas is halved, the pressure will also become half of the original pressure.
Thus, B is the correct answer.
Step-by-step explanation:
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