Question

a closed cylindrical brick tank has a diameter of 3.5 m and a height of 8 M what is the volume of the tank how much will it cost to paint the curved surface and the top of the tank if the rate is Rs 5 per metre square plzz answer fast well the answer of the question is 77m^3,rupees488.13. but I don't know how plzz help me to understand

Answer 1

Given:

⇒ Diameter of cylindrical tank = 3.5 m.

⇒ Radius of the cylindrical tank = 1.75 m.

⇒ Height = 8 m.

(i)

We know that volume of tank = πr^2h

⇒ (22/7) * (1.75)^2 * 8

⇒ 9.625 * 8

⇒ 77m^3.

(ii)

We know that Lateral surface area = 2πrh

⇒ 2 * (22/7) * (1.75) * (8)

⇒ 2 * 22 * 0.25 * 8

⇒ 88.

Total amount to be painted = LSA + Area of circle

⇒ 88 + [(22/7) * (1.75)^2]

⇒ 88 + [9.625]

⇒ 97.625.

∴Cost of painting per m^2 = 5.

Cost of painting 97.625 m^2 = 5 * 97.625

                                                = 488.125

                                                = 488.13.

Therefore:

⇒ Volume of the tank = 77m^3.

⇒ Total amount = 488.13

Hope this helps!

Answer 2

Total amount = 488.13