A closed cylindrical tank of diameter 14 m and height 5 m is made from a sheet of metal.How much sheet of metal will be required?
Answers
Answered by
267
In this case we will calculate the Total surface area of the cylindrical tank which will be eaqual to the area of metal sheet required.
TSA = 2*pi*r (h+r)
= 44 (12)
528 m^2
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TSA = 2*pi*r (h+r)
= 44 (12)
528 m^2
[Please mark as brainliest]
Answered by
137
Here we have closed cylinder, means Total Surface Area (TSA). And the TSA of acylinder is 2pi x r x (r + h), Right?
According to question,
diameter of the cylindrical tank = 14m
radius will be 14/2 = 7m
height of the cylinderical tank = 5m
Applying the formula,
TSA of Cylindrical Tank = 2pi x r x (r + h)
= 2 x 22/7 x 7 x (7 + 5)
= 528 m^2
So 528m^2 of metal sheet will be required to make the tank.
According to question,
diameter of the cylindrical tank = 14m
radius will be 14/2 = 7m
height of the cylinderical tank = 5m
Applying the formula,
TSA of Cylindrical Tank = 2pi x r x (r + h)
= 2 x 22/7 x 7 x (7 + 5)
= 528 m^2
So 528m^2 of metal sheet will be required to make the tank.
Saanchi14:
my ans is 528 pls calculate
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