Question

A closed cylindrical tank of diameter 14m and height 5m is made from a sheet of metal how much sheet of metal will be required?

Answer 1

surface area of closed cylindrical tank = 2πR (h+r)
                                                             = 2*22/7*7 (5+7)
                                                             = 528 m²
∴ 528 m² of metal sheet will be required.

Answer 2

The required sheet of metal is 528 m².

Step-by-step explanation:

It is given that a closed cylindrical tank of diameter 14m and height 5m is made from a sheet of metal.

Diameter = 14m

$d=14$

$r=\frac{d}{2}=\frac{14}{2}=7m$

$h=5m$

Area of cylinder is

$Area=2\pi r(r+h)$

where, r is radius and h is height of the cylinder.

Substitute r=7, $\pi=\frac{22}{7}$ and h=5 in the above formula.

$Area=2(\frac{22}{7}) (7)(7+5)$

$Area=44(12)$

$Area=528$

Therefore, the required sheet of metal is 528 m².

#Learn more:

A closed cylindrical tank of cylindrical tank of radius 7m and height 3 mis made from a sheet of metal. How much of metal required.

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