Question

A closed cylindrical tank of radius 14m and height 8m is made from a sheet of metal. How much sheet of metal is required? ( take π = 22/7)

Answer 1

Answer :

• Metal sheet required = 1936 m².

S O L U T I O N :

Given,

• Height of cylindrical tank (h) = 8 m
• Radius of cylindrical tank (r) = 14 m

To Find,

• How much sheet of metal is required.

Explanation,

[ Note :- Total surface area of a cylindrical tank = Sheet of a metal is required. ]

We know that,

Total surface area of cylindrical tank = 2πr(r + h)

[ Put the values ]

=> TSA = 2 × 22/7 × 14 × (14 + 8)

=> TSA = 2 × 22 × 2 × (22)

=> TSA = 44 × 2 × (22)

=> TSA = 88 × 22

=> TSA = 1936 m²

.°. Total surface area of a cylindrical tank = Sheet of a metal is required.

=> Sheet of a metal is required is 1936 m².

Therefore,

1936 m² sheet of metal is required.

Answer 2

Given:-

• Radius of cylindrical tank = 14 m.
• Height of cylindrical tank = 8 m.

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To find:-

• Sheet of metal required?

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Solution:-

• $\sf{\pi = \dfrac{22}{7}}$

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★ Formula used:-

$\star{\boxed{\sf{\orange{TSA\: of\: cylindrical\: tank = 2\pi r( r + h)}}}}$

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$\large{\tt{\longmapsto{2 \times \dfrac{22}{7} \times 14(14 + 8)}}}$

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$\large{\tt{\longmapsto{2 \times 22 \times 2 \times 22}}}$

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$\large{\tt{\longmapsto{44 \times 2 \times 22}}}$

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$\large{\tt{\longmapsto{88 \times 22}}}$

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$\boxed{\large{\tt{\longmapsto{\red{1936\: m^2}}}}}$

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Hence, the total surface area of cylindrical tank is 1936 m².