Chemistry, asked by ravijaddaravijadda03, 1 month ago

A closed end manometer is filled with Hg
as shown in the following diagram at
27°C and volume of the bulb is 150 mL.
At this temperature, the vapour pressure
of water is 28 mm of Hg. If the bulb con
tains 0.001 mol of O2(g) then the volume
of liquid water
= 0.082 L.atm mol-'K-!)
ml (Given that R​

Answers

Answered by tpalak105
3

Answer:

27 mol answer

Explanation:

152/760 × Vo2 = 0.001 × 0.0821 ×300k

Vo2 = 123ml

Vk2O = 150-Vo2 = 150 - 123 = 27ml

hope it helps you

Answered by Sujeetkuverma
2

Answer:

hey

how are you

have a nice dp

can we meet

meet.goo csr-yrhi-yom

Similar questions