A closed gas cylinder is divided into two parts by a piston held tight. The pressure and volume of gas in two parts respectively are( p, 5v) and (10p ,v). If now the piston is left free and the system undergoes isothermal process , then the volume of the gas in two parts respectively are.
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Hey buddy,
◆ Answer-
V1' = 10V/11
V2' = 20V/11
◆ Explaination-
# Given-
P1 = P
P2 = 10P
V1 = 5V
V2 = V
# Solution-
As piston is allowed to move freely, pressure on each side will be equal.
P' = (P1+P2)/2
P' = (P+10P)/2
P' = 11P/2
Applying Boyle's law to bubble 1,
P1V1 = P'V1'
V1' = P1V1/P'
V1' = P×5V / 11P/2
V1' = 10V/11
Also applying that to bubble 2,
P2V2 = P'V2'
V2' = P2V2/P'
V2' = 10P×V / 11P/2
V2' = 20V/11
Hope this helps...
◆ Answer-
V1' = 10V/11
V2' = 20V/11
◆ Explaination-
# Given-
P1 = P
P2 = 10P
V1 = 5V
V2 = V
# Solution-
As piston is allowed to move freely, pressure on each side will be equal.
P' = (P1+P2)/2
P' = (P+10P)/2
P' = 11P/2
Applying Boyle's law to bubble 1,
P1V1 = P'V1'
V1' = P1V1/P'
V1' = P×5V / 11P/2
V1' = 10V/11
Also applying that to bubble 2,
P2V2 = P'V2'
V2' = P2V2/P'
V2' = 10P×V / 11P/2
V2' = 20V/11
Hope this helps...
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