a closed iron tank 12 metre long 9 metre wide and 4 metre deep is to be made. determine the cost of iron sheet used at the rate of rupees 5 per metre sheets it is being 2 metre wide
Answers
AnswEr :
• we will find TSA of Cuboidal Tank :
⇒ TSA = 2 × (lb + bh + hl)
⇒ TSA = 2 × (12.9 + 9.4 + 4.12)
⇒ TSA = 2 × (108 + 36 + 48)
⇒ TSA = 2 × 192 m²
⇒ TSA = 384 m²
• length of Iron Sheet Required :
⇒ Length Required =
⇒ Length Required =
⇒ Length Required = 192 m
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• cost of Iron Sheet will be :
⇒ Total Cost = Length × Rate
⇒ Total Cost = 192 m × Rs. 5
⇒ Total Cost = Rs. 960
⠀
∴ Cost of Iron Sheet Required is Rs. 960
To Find :----
- cost of iron sheet used ?
Given :------
- length of tank = 12m
- Breadth of tank = 9m
- Depth of tank = 4m
- rate of iron sheet = 5/metre
- width of iron sheet = 2metre
Formula used :-----
- Total surface area of cuboid = 2(lb+bh+hl)
- length of iron sheet = Total area/width of iron sheet .
first we calculate total surface area of tank ,
TSA = 2(lb+bh+hl)
putting values we get:----
Now, length of iron sheet = Total Area/width of iron sheet
Now, cost of 1metre iron sheet = Rs.5
so, cost of 192metre iron sheet = 192×5 = Rs.960 .
⛬ cost of iron sheet will be Rs.960 ..
(Hope it helps you)
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➠ Volume of cuboid = length × width × Height
➠ Diagonal of cuboid = √(l²+b²+h²)
➠ CSA of cuboid = 2(l+b)×h