Question

a closed metal cylindrical container has a base radius of 5 cm and height of 12find the total surface area of container​



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Answer 1

Explanation:

Given :

a closed metal cylindrical container has a base radius of 5 cm and height of 12

To find :

find the total surface area of container

Solution :

$\sf{Total \: surface \: area \: of \: container \: = \: 2 \pi rh + 2 \pi r^{2} } \\ \\ \implies \sf{2 \times 3.14 \times 5 \times 12 + 2 \times 3.14 \times {5}^{2} } \\ \\ \implies\sf{6.28 \times 60 + 6.28 \times 25} \\ \\ \implies \sf{376.8 + 157} \\ \\ \implies\boxed{\underline{\sf{533.8}\:m^{2}}}$

Extra information :

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

Answer 2

Explanation:

The Total Surface area of Container is 534.14 sq cm.

step by step explanation:

We know,

Total Surface Area = 2πr(r+h) sq units

Here, radius (r)= 5cm and height (h) = 12cm

Therefore,

2πr(r+h)

= 2×22/7×5(5+12)

= 220/7(17)

= 31.42×17

= 534.14