A closed metalic cylinder has diameter 56 and hieght 272 cm find the cost of the metal used if its cost 80 rupees per meter square.
Answers
Given :-
Diameter of the cylinder = 56cm
Therefore it's radius = 56/2 (since the radius is half of the length of it's diameter)
= 28cm
Height of the cylinder = 272cm
Since it's a closed cylinder, we've to find it's total surface area TSA to find the total cost.
Formula to find the TSA of a cylinder = 2πr(h + r)
» It's total surface area = 2πr(h + r)
= 2 × 22/7 × 28 (272 + 28)
= 44 × 4
= 176 × 300
= 52800cm²
In m² = 52800/10000 = 5.28m²
Hence, total cost of the metal @ rupees 80 per m² = 5.28 × 80
= Rupees 422.4 final answer
Answer :-
The cost of the metal used is Rs. 422.4 .
Explanation :-
Diameter of closed metallic cylinder = 56 cm
So,
its Radius = r = 56/2 = 28 cm
& Height = h = 272 cm
________________[Given]
• We have to find the cost of metal used .
We know that,
Total surface area of metallic cylinder = 2πr(r + h)
= 2 × 22/7 × 28 × (28 + 272)
= 2 × 22 × 4 × 300
= 44 × 1200
= 52800 cm²
= 5.28 m²
Now,
Cost of making per square meter of metal = Rs.80
So,
Total cost of making the whole metal
= 5.28 × 80
= Rs. 422.4
____________________________
∴ Cost of the metal used is Rs. 422.4
____________________[Answer]