Question

a closed pipe of length 10 cm has its fundamental frequency half that of the second
overtone of an open pipe the length of open pipe

Answer 1

length of open pipe is 30cm

it is given that, a closed pipe of length 10cm has its fundamental frequency half that of the second overtone of an open pipe.

fundamental frequency of closed pipe, f = v/4l

= v/4 × 10cm = v/40 cm......(1) , where v is speed of sound.

second overtone of an open pipe, f' =3v/2l' .....(2)

a/c to question,

f = f'/2

⇒v/40cm = 1/2 3v/2l'

⇒1/40 = 3/4l'

⇒l' = 3 × 40/4 = 30 cm

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Answer 2

$\huge\bold\purple{Answer:-}$

it is given that, a closed pipe of length 10cm has its fundamental frequency half that of the second overtone of an open pipe. = v/4 × 10cm = v/40 cm...... (1) , where v is speed of sound. also read similar questions : The fundamental frequency of an open organ pipe is 300 hz