a closed rectangular box with a square base is 5 cm in height . if the volume of the box is 45 cubic cm , what is the box surface area in square meter
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volume=45cubic.cm
h=5cm,l=b square base all the side are equal
volume of a cuboid =l*b*h
45 =l*b*5
45/5= l^2
9=l^2
therefore l=3cm
therefore b=3cm
total surface area fo a cuboid=2[lb+bh+lh]
=2[3*3+3*5+3*5]
=2[9+15+15]
=2[39]
=2*39 =78sqcm
=0.0078sqm
h=5cm,l=b square base all the side are equal
volume of a cuboid =l*b*h
45 =l*b*5
45/5= l^2
9=l^2
therefore l=3cm
therefore b=3cm
total surface area fo a cuboid=2[lb+bh+lh]
=2[3*3+3*5+3*5]
=2[9+15+15]
=2[39]
=2*39 =78sqcm
=0.0078sqm
vishakha:
thanks.....
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