Question

A closed rectangular wooden box has inner dimension 90cm by 80cm by 70cm compute its capacity and the area of the tin foil needed to line its inner surface

Answer 1

volume of cuboid=l×b×h

=90×80×70
=504

Answer 2

Answer:

The capacity of the box is 504000cm^3

And the surface of the foil is 38200cm^2

Explanation:

A closed rectangular wooden box's inner dimension is 90cm by 80cm by 70cm

Let the length is X= 90cm, breath is Y= 80cm and the height is Z= 70cm.

So the capacity of the box is (X*Y*Z)=(90*80*70)=504000cm^3

The box is wrapped with inner tin surface and the surface area of the tin foil is= 2(XY+YZ+XZ)

=2{(90*80)+(80*70)+(70*90)}

=2{7200+5600+6300}

=38200cm^2