Question

A closed rigid container at 300 K contains Ngas
at 10 atm pressure and this container can bear
maximum 15 atm pressure; at what temprature
the container will burst?
(1) 350 K
(2) 400 K
(3) 450 K
(4) 425 K


Right answer with explanation is required...​

Answer 1

Answer:

according to Charles law

Answer 2

The temperature at which the container will burst is 450 K

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are the initial pressure and temperature of the gas.

$P_2\text{ and }T_2$ are the final pressure and temperature of the gas.

We are given:

$P_1=10atm\\T_1=300K\\P_2=15atm\\T_2=?$

Putting values in above equation, we get:

$\frac{10}{300K}=\frac{15}{T_2}\\\\T_2=450K$

Hence, the temperature at which the container will burst is 450 K

Learn more about gay lussac law

https://brainly.in/question/10488601

https://brainly.com/question/13040542