Chemistry, asked by Anonymous, 10 months ago

A closed system with a volume of 2.0L contains radon gas and liquid water , and the container is allowed to equilibrate at 27degrees Celsius until the total pressure is constant. What is the partial pressure of radon if the total pressure is 780 torr and the water vapor partial pressure is 1.0atm

Then some helium gas is added to the system and the total pressure increases to 1.20 atm
Now what is the new partial pressure of radon

Answers

Answered by aadi6662
0

Answer:

Key points

The pressure exerted by an individual gas in a mixture is known as its partial pressure.

Assuming we have a mixture of ideal gases, we can use the ideal gas law to solve problems involving gases in a mixture.

Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases:

\text {P}_{\text{Total}} = \text P_{\text {gas 1}} + \text P_{\text {gas 2}} + \text P_{\text {gas 3}} ...P

Total

=P

gas 1

+P

gas 2

+P

gas 3

...start text, P, end text, start subscript, start text, T, o, t, a, l, end text, end subscript, equals, start text, P, end text, start subscript, start text, g, a, s, space, 1, end text, end subscript, plus, start text, P, end text, start subscript, start text, g, a, s, space, 2, end text, end subscript, plus, start text, P, end text, start subscript, start text, g, a, s, space, 3, end text, end subscript, point, point, point

Dalton's law can also be expressed using the mole fraction of a gas, xxx:

\text P_{\text {gas 1}} = x_1 \text {P}_{\text{Total}}P

gas 1

=x

1

P

Total

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