Question

A closed system with an initial pressure of 20 atm decreases in volume from 15 liters to 3 liters while increasing in temperature from 300 K to 600K. What is the new pressure of the system?
Group of answer choices

50 atm

200 atm

2 atm

8 atm

Answer 1

Answer:

this is your first time answer

Answer 2

Answer:

The final/new pressure of the closed system, P₂, calculated is $200atm$.

Therefore, option b) $200atm$ is correct.

Explanation:

Given data,

The initial pressure of the closed system, P₁ = $20atm$

The initial volume of the closed system, V₁ = $15L$

The initial temperature of the closed system, T₁ = $300K$

The final volume of the closed system, V₂ = $3L$

The final temperature of the closed system, T₂ = $600K$

The final/new pressure of the closed system, P₂ =?

By using the Combined gas law equation given below, we can find out the final pressure of the closed system:

• $\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

After substituting the given values of pressure, volume, and temperature in the above-mentioned formula, we get:

• $\frac{20\times 15 }{300 } = \frac{P_{2}\times 3 }{600 }$
• $20\times 15 = \frac{P_{2}\times 3 }{2 }$
• $3P_{2} = 600$
• $P_{2} = 200atm$

Hence, the final/new pressure of the closed system, P₂ = $200atm$.