Physics, asked by Pragadeesh2220, 1 year ago

A closed triangular box is kept in an electric field of magnitude 2×10power3.Calculate the electric flux through vertical rectangular surface

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Answered by abhi178
0

see diagram, here it is shown that A closed triangular box. which is kept in an electric field of magnitude 2 × 10³ N/C.

electric flux is the dot product of electric field and area vector.

area vector = 10cm × 30cm = 0.03m² along direction of Electric field

so, electric flux = 2 × 10³ × 0.03

= 60 Nm²/C

hence,electric flux through vertical rectangular surface.

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