Question

A closed vessel is half filled with water. There is a hole near the top of the vessel and air is pumped out from this hole.
(a) The water level will rise up in the vessel.
(b) The pressure at the surface of the water will decrease.
(c) The force by the water on the bottom of the vessel will decrease.
(d) The density of the liquid will decreas

Answer 1

Answer ⇒ Option (b). and Option (c).

Explanation ⇒ When we take out the air from the closed vessel, it becomes vaccum, thus, pressure at the surface decreases and becomes zero, since vacuum is created. Hence, Option (b). is correct.

Now, When air is pumped out, it has become vaccum, as a regult of which water level will neither increase nor decrease, since gravity free space is created. Hence, option (a). is incorrect.

Now, Pressure increment, means that the force on an unit area is increased and vice versa.

Since, the pressure at the top is decreased, therefore, pressure at the depth of water will also decrease by the same amount, which further means the force by the water on bottom of vessel is decreased.

Hence, option(c). is correct.

We know that density does not depeds upon air, water, or any medium, thus, it will remains the same, whether air is added or removed.

Hence, option (d). is incorrect.

Hope it helps.

Answer 2

Therefore the impact the water exerts on the vessel's bottom also decreases.

Explanation:

Option (b) and (c) are correct.

• As air is squeezed out of the tube, the ambient pressure in the vessel is lowered above the water level. As a result, the pressure at the water's surface decreases.
• Therefore the impact the water exerts on the vessel's bottom also decreases. Therefore, option (b) and (c) are correct.

Pressure:- Pressure is known as the exertion of physical force on an object. That force applied to the objects is perpendicular to the surface per unit area.

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