Question

A closed wooden rectangular box made of 1 cm thick wood
has the following outer demenssens
length 22 cm, breadth 17 cm, and height 12cm.
it is filled with cement .
what is the volume of the cement in the box​

Answer 1

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$length \: of \: rectaguar \: box \: = 22 - 1 = 21cm \\ breath \: of \: rectaguar \: box \: = 17 - 1 = 16cm \\ height \: of \: rectaguar \: box \: = 12 - 1 = 11cm$

$volume \: of \: the \: box \: = l \times b \times h \\ \: \: \: \: \: \: \ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 21 \times 16 \times 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3696 \: cm {}^{3}$

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Answer 2

Step-by-step explanation:

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length of rectaguar box=22−1=21cm

breath of rectaguar box=17−1=16cm

height of rectaguar box=12−1=11cm

Volume of the box=l×b×h

=21×16×1

=3696cm³