Question

A closely wound flat circular coil of 50 turns of wire has diameter of 20 cms and it carries a current of 5 A. Determine the magnetic field intensity at the center of the circular coil.

Answer 1

Explanation:

$\bf \huge \: \: \: Question \: \: \:$

A closely wound flat circular coil of 50 turns of wire has diameter of 20 cms and it carries a current of 5 A. Determine the magnetic field intensity at the center of the circular coil.

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$\bf \huge \: \: \: Given \: \: \:$

• closely wound flat circular coil of 50
• turns of wire has diameter of 20 cms
• it carries a current of 5 A.

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$\bf \huge \: \: \: To \: Find \: \:$

• Determine the magnetic field intensity at the center of the circular coil.

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$\bf \huge \: \: \: solution \: \: \:$

• N = 50 turns

We Have Formula:-

Flux density :-.

$\bf \: B \: = \frac{ u_{0}i }{2r} \times n$

Putting the value:-

$\bf \: </u></strong><strong><u>B</u></strong><strong><u> </u></strong><strong><u>=</u></strong> \frac{5\pi\times{10}^{ - 7}\times5\times50 }{2\times20/100}$

$\bf \: B =</u></strong><strong><u>\frac{5\pi\times{10}^{ - 7</u></strong><strong><u>}</u></strong><strong><u>\times</u></strong><strong><u>2</u></strong><strong><u>5</u></strong><strong><u>0</u></strong><strong><u>\times</u></strong><strong><u>1</u></strong><strong><u>0</u></strong><strong><u>0</u></strong><strong><u>}{</u></strong><strong><u>4</u></strong><strong><u>0</u></strong><strong><u>} </u></strong><strong><u> \\ </u></strong><strong><u>$

$\bf \: B =\frac</u></strong><strong><u>{5\pi\times</u></strong><strong><u>{10}^{ - 7}</u></strong><strong><u>\times</u></strong><strong><u>2</u></strong><strong><u>5</u></strong><strong><u>0</u></strong><strong><u>0</u></strong><strong><u>0</u></strong><strong><u>}{40} </u></strong><strong><u> \\ </u></strong><strong><u>$

$\bf \: B =\frac{5\pi\times{10}^{ - 7}\times</u></strong><strong><u>1</u></strong><strong><u>0</u></strong><strong><u>0</u></strong><strong><u>0</u></strong><strong><u>\times</u></strong><strong><u>2</u></strong><strong><u>5</u></strong><strong><u>}{40} </u></strong><strong><u> \\ </u></strong><strong><u>$

$\bf \: B =\frac{5\pi\times{10}^{ - 7}\times</u></strong><strong><u>{10}^{ </u></strong><strong><u>+</u></strong><strong><u>3</u></strong><strong><u>}\times</u></strong><strong><u>2</u></strong><strong><u>5</u></strong><strong><u>}</u></strong><strong><u>{</u></strong><strong><u>40} </u></strong><strong><u> \\ </u></strong><strong><u>$

$\bf \: B =\frac{5\pi\times{10}^{ - </u></strong><strong><u>4</u></strong><strong><u>}\times</u></strong><strong><u>2</u></strong><strong><u>5</u></strong><strong><u>}</u></strong><strong><u>{40} </u></strong><strong><u> \\ </u></strong><strong><u>$

$\bf \: B =</u></strong><strong><u>9</u></strong><strong><u>.</u></strong><strong><u>8</u></strong><strong><u>2</u></strong><strong><u>\times{10}^{ - 4}</u></strong><strong><u> \\ </u></strong><strong><u>$