A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each.
The diameter of the solenoid is 1.8 cm. If the current carried is 8 A, estimate the
magnitude of B inside the solenoid near its centre.
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Answer:
A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each.
N = 5*400 = 2000
The diameter of the solenoid is 1.8 cm. The current carried is 8 A.
The magnetic field inside a long solenoid is properly calculated by using the cross product and maybe the right hand rule, but all that can be simplify into:
B = µ₀ * N * I / L
where
B is the magnetic field,
µ₀ = 1.25664 * 10^-6 T*m/A is the vacuum permeability,
N is the number of turns in the solenoid,
I is the electric current,
L is the length of the solenoid.
Put the values in the given formula
We get, magnetic field
B = 0.025133 T
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