A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each.
The diameter of the solenoid is 1.8 cm. If the current carried is 8 A, estimate the
magnitude of B inside the solenoid near its centre.
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Explanation:
Length of solenoid L=80cm=0.8m
Diameter of solenoid d=1.8cm
As d<<L, thus we can treat the solenoid as solenoid of infinite length w.r.t its diameter.
Current flowing through the solenoid I=8.0 A
Total number of turns N=5×400=2000 turns
Number of turns per unit length n= L N
∴ n= 0.82000 =2500
Magnetic field at the center of solenoid B=μ o nI
∴ B=4π×10 −7 ×2500×8.0
We get B=2.5×10 −2 T
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