Question

A closely wound solenoid of 1000 turns and
area of cross-section 2 x 104 m² carries a
current of 1 A. It is placed in a horizontal plane
with its axis making an angle of 30° with the
direction of uniform magnetic field of 0.16 T.
Calculate the torque acting on the solenoid.
(July 18]​

Answer 1

Explanation:

Given :-

• No. of turn N = 1000
• Area of cross section A = 2 × 10⁴ m²
• Current I = 1 A
• Magnetic Field B = 0.16 T
• Angle b/w solenoid and field Ø = 30⁰
• Torque T = ?
• T = N I B A sin Ø
• T = 1000 × 1 × 0.16 × 2 × 10⁴ sin 30⁰
• T = 1000 × 1 × 0.16 × 2 × 10⁴ × 1/2
• T = 1.6 × 10⁶