A closely wound solenoid of 2000 turns and area of cross-section 1.6 x 10⁻⁴ m², carrying a current of 4.0 A, is suspended through its centre allowing it to turn in a horizontal plane.What is the magnetic moment associated with the solenoid?
Answers
Answer :
M = 1.28 Am².
Explanation :
(Part A)
Given that :
A closely wound solenoid of 2000 turns.
The area of cross-section 1.6 x 10⁻⁴ m².
Carrying a current of 4.0 A.
To Find :
The magnetic moment associated with the solenoid.
Solution :
We have,
Number of turns , N = 2000
Current , I = 4 A
Cross section area A = 1.6 × 10⁻⁴ m².
We know that :
Put the given values :
Answer = M = 1.28 Am².
The direction of is along the axis of the solenoid in the direction related to sense of current through "The Right handed screw rule"
》 A closely wound solenoid of 2000 turns and area of cross-section 1.6 x 10⁻⁴ m² carrying a current of 4.0 A, is suspended through its centre allowing it to turn in a horizontal plane.
Here..
• Number of turns (N) = 2000
• Area of cross-section (A) = 1.6 × 10-⁴ m²
• Current (I) = 4 A
We have to find theMmagnetic moment (M).
We know that..
Put the known values in above formula to find Magnetic moment.
=> M = 2000 × 1.6 × 10-⁴ × 4
=> M = 3200 × 10-⁴ × 4
=> M = 12800 × 10-⁴
=> M = 1.28
Units :-
M = NIA
- Unit of N = no units
- Unit of I = A (ampere)
- Unit of A = m² (meter square)
So,
=> M = A-m²
Magnetic moment associated with the solenoid is 1.28 A-m².
_____________________________
☆ Some Basic of Magnetism :
- The earth beahves as a bar magnet.
- When a magnet is suspended freely, it comes to rest along north-south direction.
- Like poles repel each other and unlike poles attract each other.