Question

A closely wound solenoid of 800 turns and area of cross section 2.5 x 10⁻⁴ m² carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

Answer 1

Here is your answer

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N(no. of turns ) = 800 ,

Area of cross section (A) = 2.5x 10 ^-4

current in the solenoid(I) = 3A

NOw,

using magnetic moment

m =NIA

m = 800 x 3 x 2.5 x10^-4

m = 2400 x 2.5 x 10 ^-4

m = 24 x 2.5 x 10^ -2

m = 60 x 10 ^-2

m = 0.6 j/T

Answer 2

Answer:

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Explanation:

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