Question

A cloth is 7m long and 2m wide.If sheena wants to lace it around,how much lace is required?

Answer 1

Answer:

length of the lace required=perimeter of rectangle

P(rectangle)=2(length +breadth)

=2(8+5)

=2(13)

=26

therefore, Komal requires 26m length of lace.

Hope i was able to help you!

Step-by-step explanation:

Answer 2

Answer:

$\blue\bigstar$ 18m of lace is required to lace around the cloth.

SOLUTION

Lace is put along the perimeter of the cloth .

$\bigstar$The cloth is in the shape of a rectangle.

Perimeter of a rectangle = 2(Length + Breadth) = 2(l+b)

Here ,

Breadth(b) of the rectangular cloth = 2m.

Length(l) of the rectangular cloth = 7m.

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 7m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 2m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

Perimeter of the rectangular cloth = 2(7+2)

$\implies$

Perimeter of the rectangular cloth = 2×9

$\implies$

Perimeter of the rectangular cloth = 18m.

$\red\bigstar$ Therefore,18m of lace is required to lace around the cloth.