A cloth merchant prepares and sells court and trousers only there is a space
in godown to store 100 units only and he has capital of Rs 24000. A court
cost Rs 1800 and trouser’s cost Rs 900. He earns profit of Rs. 150 on each
court and Rs 60 on trouser. Give a mathematical formulation of linear
program plan to get maximum profit. Obtain its solution by graphical
method. Assume that all court and trouser made is sold.
Answers
Given : A cloth merchant prepares and sells court and trousers only there is a space in godown to store 100 units only and he has capital of Rs 24000. A court cost Rs 1800 and trouser’s cost Rs 900. He earns profit of Rs. 150 on each court and Rs 60 on trouser.
To find : maximum profit.
Solution:
Number of Court = C
Number of Trousers = T
C + T ≤ 100
1800C + 900T ≤ 24000
=> 6C + 3T ≤ 80
Profit = 150C + 60T
Court Trouser Profit
0 26 1560
1 24 1590
2 22 1620
3 20 1650
12 2 1920
13 0 1950
Hence Maximum profit when
Court = 13
Maximum profit = 1950
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