Question

A cm of iron weights 8 gm. The weight of an iron hemisphere of radius 3 cm

Answer 1

Hey dear here is your answer!!!!!

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We have been given that the radius of the hemisphere is 3 cm.

And we also know that volume of a hemisphere is - $\frac{2}{3}$ πr³

Substitute the value of 'r' in the formula:-

= $\frac{2}{3}$ x $\frac{22}{7}$ x 27

= $\frac{1188}{21}$

= 56.57 cm³ approx

The weight of 1 cm³ of iron is 8 gm.

So, the weight of 56.57 cm³ of iron would be:-

= 56.57 x 8

= 452.57 gm

So, the answer is 452.57 gm !

$\large\boxed{\large\boxed{\large\boxed{Solved !}}}}$

❣️⭐ Hope it helps you dear...⭐⭐❣️❣️

Answer 2

Here is your answer.....