Math, asked by rakshan28, 1 year ago

A coach can carry 48 passengers . How many coaches will you need to carry 1100 passengers ? How many seats will be remaining?

Answers

Answered by Satyamssingh
1
48 ×24 =1152
1152 - 1100
52 seats are left.

rakshan28: you are wrong
Satyamssingh: what
Satyamssingh: ...
Satyamssingh: your answer is.......
rakshan28: try if u can't find the answer i will tell u
rakshan28: I will tell the answer
rakshan28: 1100/48=22 and 44 remaining . Now this is for the passengers
rakshan28: so accommodate 44 passengers u need a coach so the coach becomes 23 and 48 seats - 44 passengers =4 seats remaining
rakshan28: so answer is 23 coaches and 4 seats remaining . Think man
Answered by barnadutta2015
0

Answer: 23 coaches is required to carry 1100 passengers and 4 seats will be remained.

Step-by-step explanation:

A single coach which can carry 48 passengers
we can write it as
48 passengers = 1 coach

1 passenger = 1/48 coach

1100 passenger= 1/48 x 1100

Solving we get, 22 coaches will carry 1056 passengers and the remaining 44 can come in the next coach

23rd coach has 48 seats capacity. The remaining 44 can adjust on that.

Remaining seats = 48 - 44 = 4 seats

Hence, 23 coaches is required to carry 1100 passengers and 4 seats will be remained.

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https://brainly.in/question/38722082
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