A cocktail was prepared by mixing 20.0g ethanol to 150 g water at 25oC. Pure water has a vapor pressure of 23.76 torr. What would be the new vapor pressure?
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According to Raoult's law, the vapor pressure of a solution, with the solute being non-reacting, none volatile, and non-electrolytic, at a certain temperature is equal to the mole fraction of the solvent in the solution multiplied by the vapor pressure of the pure solvent at that given temperature.
Answer and Explanation: 1
We are given
The mass of the ethanol:
m
e
=
20.0
g
The mass of the water:
m
w
=
150
g
The vapor pressure of...
Explanation:
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