Math, asked by Vanshars, 6 months ago

A code consists of two different letters followed by 4 different digits. How many total different codes can be generated. class 11 permutation and combination

Answers

Answered by rv21060
0

Step-by-step explanation:

There are as many codes as there are ways of filling 4 vacant places in succession by the first

10 letters of the English alphabet, keeping in mind that the repetition of letters is not allowed.

The first place can be filled in 10 different ways by any of the first 10 letters of the English

alphabet following which, the second place can be filled in by any of the remaining letters in 9

different ways. The third place can be filled in by any of the remaining 8 letters in 8 different

ways and the fourth place can be filled in by any of the remaining 7 letters in 7 different ways.

Therefore, by multiplication principle, the required numbers of ways in which 4 vacant places

can be filled is 10 * 9 * 8 * 7 = 5040

Hence, 5040 four-letter codes can be formed using the first 10 letters of the English alphabet,

if no letter is repeated.

Answered by Anonymous
16

Answer:

i m in 8th standard sorry i don't know

Similar questions