Question

A code word consists of two distinct english alphabets followed by two distinct numbers from 1 to 9.For example, AK47 is a code word. Hpw many such words are there?how many of them will end with an even number

Answer 1

this is Ur required result

Answer 2

Answer: 46800

Step-by-step explanation:

There are in all 26 English alphabets. We have to choose 2 distinct alphabets.

First alphabet can be selected in 26 ways. Second alphabet can be selected in 25 ways. Again out of 9 Digits (1 to 9), first digit can be selected in 9 ways. second digit can be selected in 8 ways.

Thus, the number of distinct codes

=26×25×9×8

=46800