A coil develops heat of 800 cal/sec . When 20 volts is applied across its ends . The resistance of coil is .....(1cal = 4.2joule).... Pls urgent
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heat dissipated per second = power = V² / R
R = 20² / ( 800 * 4.2 ) ohms = 1/8.4 ohms
R = 20² / ( 800 * 4.2 ) ohms = 1/8.4 ohms
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