A coil draws a current of 1 ampere and power 100 watt from an ac source of 110v and
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Given : A coil draws a current of 1.0 ampere and a power of 100 watt from an A.C. source of 110 volts and 5√22 /π hertz.
To Find : the inductance and resistance of the coil.
Solution:
P = I²R
=> 100 = (1)²R
=> R = 100 Ω
Resistance of coil = 100 Ω
Z = V/I
=> Z = 110/1
=> Z = 110 Ω
Z² = R² + (ωL)²
=> 110² = 100² + (ωL)²
=> 2100 = (ωL)²
=> ωL = √2100
=> 2πfL = 10 √21
f = 5√22 /π
=> π f = 5√22
=> 2 (5√22) L= 10 √21
=> L = √21 / √22
Inductance of coil = √21 / √22 H
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