Question

A coil has 300 turns each of area 0.05m.
i] Find the current through the coil for which the magnetic moment of the coil
will be 4.5Am.
ü] It is placed in a uniform magnetic field of induction 0.2T with it's magnetic
moment making an angle of 30° with B. Calculate the magnitude of the
torque experienced by the coil.​

Answer 1

Answer:

question ek jaisa hai par question ke no.change hai so,esi type se aap kar sakte hai.

Explanation:

Correct option is

C

3.93 N m

Given that,

Number of turns, N=100

Radius of coil, r=10 cm=0.1 m

Current in the coil, i=5 A

Magnetic moment of the coil, M=Ni(πr2)

Magnetic field, B=0.5 T

θ=90o−60o=30o

Torque that must be applied to the coil, τ=Ni(πr2)×B×sin θ=100×5×(3.14×0.12)×0.5×sin30o=3.93 Nm

So, correct option is (C)