Physics, asked by joonchim811, 4 days ago

a coil has inductance of 0.2 h and resistance of 40 ohm it is connected to 220 volt 50 hz ac source calculate power dissipated in circuit​

Answers

Answered by studinesh6297
5

Answer:

220 volt × 50 hz

11000

11000 ÷ 40

275

275 × 0.2

55 answer

Answered by abhijattiwari1215
0

Answer: a coil has inductance of 0.2 h and resistance of 40 ohm it is connected to 220 volt 50 hz ac source .The power dissipated in circuit​ is 70.1 watt

Explanation:

a coil has inductance of 0.2 h and resistance of 40 ohm it is connected to 220 volt 50 hz ac source. The power dissipated in circuit is 70.1 Watt​

Given - resistance in the circuit = 40 Ω

Inductance in the circuit L = 0.2 H

Erms = 220 V

frequency = 50 Hz

so,Z = √R²+XL²= √R²+(2πfL)²

Z = \sqrt(40) + (2\pi * 50 * 0.4 )²

Z = 165.7

Irms = Erms / Z = 220/165.7 = 1.32 A

Power = 220× 1.32 ×40 / 165.7

        = 70.1 W

To know more about inductance from the given link

https://brainly.in/question/16170855

To know more about power from the given link

https://brainly.in/question/30273352

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