a coil has inductance of 0.2 h and resistance of 40 ohm it is connected to 220 volt 50 hz ac source calculate power dissipated in circuit
Answers
Answer:
220 volt × 50 hz
11000
11000 ÷ 40
275
275 × 0.2
55 answer
Answer: a coil has inductance of 0.2 h and resistance of 40 ohm it is connected to 220 volt 50 hz ac source .The power dissipated in circuit is 70.1 watt
Explanation:
a coil has inductance of 0.2 h and resistance of 40 ohm it is connected to 220 volt 50 hz ac source. The power dissipated in circuit is 70.1 Watt
Given - resistance in the circuit = 40 Ω
Inductance in the circuit L = 0.2 H
Erms = 220 V
frequency = 50 Hz
so,Z = √R²+XL²= √R²+(2πfL)²
Z = ²
Z = 165.7
Irms = Erms / Z = 220/165.7 = 1.32 A
Power = 220× 1.32 ×40 / 165.7
= 70.1 W
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