Question

A coil having 10 ohm resistance and 0.1 h inductance is connected across 230v 50Hz AC supply calculat impedance

Answer 1

Answer:

Given that,

The Frequency of AC signal,f=50HZ

Inductance,L=0.1H

Resistance of the resistor,R=10ohm

Thus the impedance of the inductor,=XL

=wL=(2πf)L

=2×π×50×0.1

=100×π×0.1

=10πohm

The net impedance of the circuit,

=√xL²+R²

=√100+100π²

=10(√1+π²)

=99.7Ω

Explanation:

Hope it helps you frnd......