Question

A coil having a resistance of 5
ohms, and inductance of 0.1 H is
connected in series with a
capacitor of 50 uF. A supply of 200
Vrms is applied to the circuit. What
is the maximum current that can
flow in the circuit?
0 71.2 A
O
40 A
041.2 A
O 70 A​

Answer 1

Explanation:

ω=2πf=2π×50=100π=314rads-1

Xc= 1/ωc =1 /314×100×10 −6 =31.84Ω

XL=ωL=314×0.5=157Ω

Z=

$\sqrt{r {}^{2} } (x \: l - xc)2$