Question

A coil having N turns and resistance R Ω is connected to a galvanometer of resistance 4R Ω. This combination is moved in time I seconds from a magnetic flux Φ₁ Wb to Φ₁ Wb. What is the induced current in the circuit?Answer the Given question in brief.

Answer 1

Dear Student,

◆ Answer -

I = -N(Φ₂-Φ₁)/5Rt

◆ Explanation -

Total resistance in the circuit is -

R' = R + 4R

R' = 4R

Also EMF induced in the coil is given by -

V = -N.∆Φ/t

V = -N(Φ₂-Φ₁)/t

Now, induced current in the circuit will be -

I = V/R'

I = [-N(Φ₂-Φ₁)/t]/5R

I = -N(Φ₂-Φ₁)/5Rt

Hope this helps you...