Question

A coil in the heater consume power P on passing current. If it is cut into halves and joined in parallel, it will consume power
(a) P
(b) P/2
(c) 2P
(d) 4P

Answer 1

Answer:

P/2 is the answer. Tq for

Answer 2

Answer:

it will consume power: 4p.

a coil in the heater consumes power = p

if it is out into halves and joined in parallel, then the resistance of the coil gets reduced to half = r/2

$p = v^2/r$

$p' = (v^2/ r/2) + (v^2 / r/2)\\ = (2v^2 / r/2) \\= 4 v^2/r$

p' = 4 p