Question

A coil of 10 Henry self inductance and 10 ohm resistance is joined with a battery of 50 volt .The stored energy in the coil is

Answer 1

Answer:125 joules

Explanation:I = V/R

I = 50/10 = 5A

Energy stored in coil = 1/2LI²

E = 1/2x10x(5)²

E = 125 joules

Answer 2

The stored energy in the coil is 125 joules.

Given:

Self-inductance = 10 H = L

Resistance = 10 Ω = R

Voltage = 50 V = V

To find:

Energy stored in the coil = ?

Solution:

The energy stored in the magnetic field is given by the formula:

$E=\frac{1}{2} L I_{0}^{2}$

Where,

L = Inductance

I = Current

Since, the value of current is not given.

On applying, Ohm's law, we can determine the value of current flowing through the coil. Thus, the current is given by the formula.

$I_{0}=\frac{V}{R}$

On substituting the given values, we get,

$I_{0}=\frac{50}{10} = 5 \ A$

Now, on substituting values on the energy formula, we get,

$E=0.5\times 10\times (5)^2$

$\therefore E = 125 \ J$