Question

A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10-5 weber. The inductance is
(a) 0.2 mH
(b) 2.0 mH
(c) 0.02 mH
(d) 0.002 H

Answer 1

Explanation:

Li=N∅

L×5=100×10

−5

L=0.2mH

Answer 2

Answer:

The inductance is 0.2 H.

Explanation:

We know that,

Inductance, L= $\frac{N\emptyset}{i}$

According to the question,

Number of turns, N= 100

Magnetic flux, $\emptyset$ = $10^{-5}$ weber

Current, i = 5 mA

∴

Inductance, L= $\frac{100\times10^{-5} }{5\times10^{-3} }$

= 0.2 H

The correct answer is 0.2 H