Question

A coil of 100 turns is lying in a magnetic field of 1T as shown in the figure. A current of 1A is flowing in this coil. The torque acting on the coil will be​

Answer 1

$\Large{\underline{\underline{\bf{Answer:-}}}}$

Torque = 2 N/m

$\Large{\underline{\underline{\bf{GiVen:-}}}}$

A coil of 100 turns is lying in a magnetic field of 1T as shown in the figure. A current of 1A is flowing in this coil.

$\Large{\underline{\underline{\bf{To Find:-}}}}$

Torque acting on the coil.

$\Large{\underline{\underline{\bf{Solution:-}}}}$

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Area of coil = 0.2 × 0.1 = 0.02 m².

So,

let magnetic moment of coil be M ;

$\therefore \: M =n\times i \times area$

$❥ \: M = 100\times1\times0.02$

$❥ \: M = 2 \: amp \: {m}^{2}$

So,

Magnetic torque be $\tau$.

$\therefore \: \tau = B \times M \times \sin( {90}^{ \circ} )$

$❥ \: \tau = B \times M \times 1$

$❥ \: \tau = 1 \times( 2 )$

$❥ \: \tau =2 \: N/m$

So,

Final answer is:

$\boxed{ \large{ \bold{ \underline{ \: \tau =2 \: N/m}}}}$

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Answer 2

Answer:

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