Question

A coil of 20 Ω resistance has an inductance of 0.2 H and is

connected in parallel with a 100 µF capacitor. Calculate the

frequency at which the circuit will act as a non-inductive

resistance of R ohms. Find also the value of R.​

Answer 1

Explanation:

sry I don't know the answer

Answer 2

The resistance value at the resonance is 100 Ohms

Given:

A coil of 20 Ω resistance has an inductance of 0.2 H and is connected in parallel with a 100 µF capacitor

To Find:

To Calculate the frequency at which the circuit will act as a non-inductive

resistance of R ohms.

Solution:

The frequency at which resonance occurs is,

$f_{r} = \sqrt{\frac{1}{Lc}- \frac{R^v}{L^v} }$

Frequency at which the circuit will act as a non-inductive resistance ,

= 200Hz

R value at the resonance,

= $\frac{L}{C(R) }$

= $\frac{0.2}{100(10^-6)(20)}$

R = 100Ω

Hence, the resistance at the resonance is   100Ω

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